The P-V diagram of a system undergoing thermo | vedclass

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(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta Q$ is the heat supplied to the system,$\Delta U$ is th

Vedclass · Accepted Answer

$134$

Vedclass · Answer

(D) According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta Q$ is the heat supplied to the system,$\Delta U$ is the change in internal energy,and $\Delta W$ is the work done by the system.Given,heat supplied $\Delta Q = 20 \ cal = 20 	imes 4.2 \ J = 84 \ J$.The work done on the system is $50 \ J$,which means the work done by the system is $\Delta W = -50 \ J$.Using the first law: $\Delta Q = \Delta U + \Delta W$$84 \ J = \Delta U + (-50 \ J)$$\Delta U = 84 \ J + 50 \ J = 134 \ J$.Therefore,the change in internal energy is $134 \ J$.

The $P-V$ diagram of a system undergoing thermodynamic transformation is shown in the figure. The work done on the system in going from $A$ $\rightarrow B$ $\rightarrow C$ is $50 \ J$ and $20 \ cal$ of heat is given to the system. The change in internal energy between $A$ and $C$ is ...... $J$.

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