The d-orbitals which are involved in the hybr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The central atom in $ICl_4^{-}$ is Iodine $(I)$.$2$. The valence shell electronic configuration of $I$ is $5s^2 5p^5$.$3$. The steric number

Vedclass · Accepted Answer

$d_{z}^2, d_{x^2-y^2}$

Vedclass · Answer

(A) $1$. The central atom in $ICl_4^{-}$ is Iodine $(I)$.$2$. The valence shell electronic configuration of $I$ is $5s^2 5p^5$.$3$. The steric number is calculated as: $\frac{1}{2} 	imes (V + M - C + A) = \frac{1}{2} 	imes (7 + 4 - 0 + 1) = 6$.$4$. $A$ steric number of $6$ corresponds to $sp^3d^2$ hybridization.$5$. In $sp^3d^2$ hybridization,the two $d-$orbitals involved are $d_{z}^2$ and $d_{x^2-y^2}$.

The $d-$orbitals which are involved in the hybridization of the central atom in $ICl_4^{-}$ are:

Similar Questions

In a triangle $ABC$,if the midpoints of sides $AB, BC, CA$ are $(3,0,0), (0,4,0), (0,0,5)$ respectively,then $AB^2 + BC^2 + CA^2 = $

The statement $\sim (p \leftrightarrow \sim q)$ is

If $\int \frac{d \theta}{\cos ^{2} \theta(\tan 2 \theta+\sec 2 \theta)}=\lambda \tan \theta+2 \log _{e}|f(\theta)|+C$ where $C$ is a constant of integration,then the ordered pair $(\lambda, f(\theta))$ is equal to

If $f(x) = \sin x + \cos x$,then $f\left(\frac{\pi}{4}\right) f^{(iv)}\left(\frac{\pi}{4}\right)$ is equal to

Write down the Boolean expression for the output $Y$ of the system shown in the figure.

Vedclass Test Series

Exam Paper Generator

Online Exam Module