The pH of a sample of vinegar is 3.76. Calcul | vedclass

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(B) The relationship between $pH$ and hydrogen ion concentration $[H^+]$ is given by the formula: $pH = -\log[H^+]$.Given $pH = 3.76$,we have $3.76 =

Vedclass · Accepted Answer

$1.738 	imes 10^{-4}$

Vedclass · Answer

(B) The relationship between $pH$ and hydrogen ion concentration $[H^+]$ is given by the formula: $pH = -\log[H^+]$.Given $pH = 3.76$,we have $3.76 = -\log[H^+]$.Therefore,$\log[H^+] = -3.76$.To find $[H^+]$,we take the antilog of $-3.76$: $[H^+] = 10^{-3.76}$.$[H^+] = 10^{0.24} 	imes 10^{-4}$.Since $10^{0.24} \approx 1.738$,the concentration is $[H^+] = 1.738 	imes 10^{-4} \ mol \ dm^{-3}$.

The $pH$ of a sample of vinegar is $3.76$. Calculate the concentration of hydrogen ion in it in $mol \ dm^{-3}$?

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