The IUPAC name of K_{2}[Ni(CN)_{4}] is | vedclass

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(A) The complex is $K_{2}[Ni(CN)_{4}]$.First,determine the oxidation state of $Ni$ in the complex $[Ni(CN)_{4}]^{2-}$.Let the oxidation state of $Ni$

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potassium tetracyanonickelate $(II)$

Vedclass · Answer

(A) The complex is $K_{2}[Ni(CN)_{4}]$.First,determine the oxidation state of $Ni$ in the complex $[Ni(CN)_{4}]^{2-}$.Let the oxidation state of $Ni$ be $x$.$x + 4(-1) = -2$$x - 4 = -2$$x = +2$.Since the complex ion $[Ni(CN)_{4}]^{2-}$ is anionic,the metal name ends in '-ate',which is 'nickelate'.The ligand $CN^-$ is named 'cyano'.Thus,the $IUPAC$ name is potassium tetracyanonickelate $(II)$.

The $IUPAC$ name of $K_{2}[Ni(CN)_{4}]$ is

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