The IUPAC name of the given organic compound | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given compound is $HC \equiv C-CH=CH-CH=CH_2$.According to $IUPAC$ nomenclature rules,when both double and triple bonds are present,the double

Vedclass · Accepted Answer

Hexa$-1,3-$dien$-5-$yne

Vedclass · Answer

(C) The given compound is $HC \equiv C-CH=CH-CH=CH_2$.According to $IUPAC$ nomenclature rules,when both double and triple bonds are present,the double bond is given preference in numbering if the set of locants is the same.Numbering from the right side gives the double bonds positions $1$ and $3$,and the triple bond position $5$.Numbering from the left side gives the triple bond position $1$,and the double bonds positions $3$ and $5$.Comparing the sets of locants: $(1, 3, 5)$ vs $(1, 3, 5)$.Since the sets are identical,the double bond is given the lower locant.Therefore,the correct numbering starts from the right: $CH_2=CH-CH=CH-C \equiv CH$ is not the structure,but $CH_2=CH-CH=CH-C \equiv CH$ is the reverse of the given structure.Given structure: $HC \equiv C-CH=CH-CH=CH_2$.Numbering from right to left: $C_1=CH_2, C_2=CH, C_3=CH, C_4=CH, C_5=C, C_6=CH$.This gives the name Hexa$-1,3-$dien$-5-$yne.

The $IUPAC$ name of the given organic compound is $HC \equiv C-CH=CH-CH=CH_2$.

Similar Questions

The $IUPAC$ name of $CH_3-CO-CH(CH_3)-CH_2-CH_2Cl$ is

The total number of $\sigma$ and $\pi$ bonds in $2-$formylhex$-4-$enoic acid is . . . . . . .

Which of the following compounds is wrongly named?

Based on the $IUPAC$ system,the tertiary butyl group is named as:

The $IUPAC$ name of $CH_3CH_2OCH(CH_3)_2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module