The pH of the solution, when(i) sodium acetat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $(i)$ Sodium acetate $(CH_3COONa)$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$. When dissolved in water, it undergoes hydroly

Vedclass · Accepted Answer

$(i)$ $pH > 7$$(ii)$ $pH < 7$

Vedclass · Answer

(A) $(i)$ Sodium acetate $(CH_3COONa)$ is a salt of a weak acid $(CH_3COOH)$ and a strong base $(NaOH)$. When dissolved in water, it undergoes hydrolysis to form a basic solution:$CH_3COO^- + H_2O \rightleftharpoons CH_3COOH + OH^-$Since the solution is basic, the $pH > 7$.$(ii)$ Ammonium chloride $(NH_4Cl)$ is a salt of a strong acid $(HCl)$ and a weak base $(NH_4OH)$. When dissolved in water, it undergoes hydrolysis to form an acidic solution:$NH_4^+ + H_2O \rightleftharpoons NH_3 + H_3O^+$Since the solution is acidic, the $pH Therefore, the correct option is $(i)$ $pH > 7$ and $(ii)$ $pH < 7$.

The $pH$ of the solution, when
$(i)$ sodium acetate is dissolved in water.
$(ii)$ ammonium chloride is dissolved in water.

Similar Questions

The $pH$ of water is $7$. When a substance $Y$ is dissolved in water,the $pH$ becomes $13$. The substance $Y$ is a salt of......

Hydrolysis of sodium acetate will give:

The $pH$ of an aqueous solution of $CH_3COONa$ of concentration $C \ M$ is given by:

If the $K_b$ value in the hydrolysis reaction $B^{+} + H_2O \rightleftharpoons BOH + H^{+}$ is $1.0 \times 10^{-6}$,then the hydrolysis constant of the salt would be

The dissociation constant of a substituted benzoic acid at $25^{\circ}C$ is $1.0 \times 10^{-4}$. The $pH$ of a $0.01 \ M$ solution of its sodium salt is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The $pH$ of the solution, when$(i)$ sodium acetate is dissolved in water.$(ii)$ ammonium chloride is dissolved in water.