The r.m.s. speed of the molecules of a gas in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The root mean square $(r.m.s.)$ speed of gas molecules is given by the formula: $V_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas con

Vedclass · Accepted Answer

$400$

Vedclass · Answer

(C) The root mean square $(r.m.s.)$ speed of gas molecules is given by the formula: $V_{rms} = \sqrt{\frac{3RT}{M}}$.Here,$R$ is the universal gas constant,$T$ is the absolute temperature,and $M$ is the molar mass of the gas.From the formula,it is evident that $V_{rms}$ depends only on the temperature $T$ and the nature of the gas (molar mass $M$).It does not depend on the number of molecules or the density of the gas.Since the temperature remains constant and the gas type does not change,the $r.m.s.$ speed remains unchanged regardless of the amount of gas leaking out.Therefore,the $r.m.s.$ speed of the remaining molecules will be $400 \; m/s$.

The $r.m.s.$ speed of the molecules of a gas in a vessel is $400 \; m/s$. If half of the gas leaks out,at constant temperature,the $r.m.s.$ speed of the remaining molecules will be ..... $m/s$.

Similar Questions

If the root mean square (rms) speed of nitrogen molecules at room temperature is $100 \ m \ s^{-1}$, then the rms speed of Helium molecules at the same temperature is

At $27\,^oC$,the $rms$ velocity of $H_2$ gas is $100\, m/s$. Find the $rms$ velocity of $O_2$ gas at $327\,^oC$.

If a container is filled with a mixture of $H_2$ and $O_2$ gases at the same temperature,then:

At what temperature is the $rms$ speed of air molecules doubled compared to its value at $NTP$?

At a given temperature,which gas has a higher speed: light or heavy?

Vedclass Test Series

Exam Paper Generator

Online Exam Module