The P-V graph of an ideal gas cycle is shown | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In a $P-V$ diagram,the slope of an adiabatic process is given by $\frac{dP}{dV} = -\gamma \frac{P}{V}$,while the slope of an isothermal process is

Vedclass · Accepted Answer

$BC$ and $DA$

Vedclass · Answer

(C) In a $P-V$ diagram,the slope of an adiabatic process is given by $\frac{dP}{dV} = -\gamma \frac{P}{V}$,while the slope of an isothermal process is given by $\frac{dP}{dV} = -\frac{P}{V}$.Since $\gamma > 1$ for any ideal gas,the adiabatic curves are steeper than the isothermal curves.Looking at the graph,the segments $BC$ and $DA$ have a greater slope compared to the segments $AB$ and $CD$.Therefore,$BC$ and $DA$ represent the adiabatic processes,while $AB$ and $CD$ represent the isothermal processes.Thus,the correct option is $C$.

The $P-V$ graph of an ideal gas cycle is shown below. The adiabatic processes are described by:

Similar Questions

$A$ system changes from the state $(P_1, V_1)$ to $(P_2, V_2)$ as shown in the figure. What is the work done by the system?

One mole of an ideal diatomic gas undergoes a transition from $A$ to $B$ along a path $AB$ as shown in the figure. The change in internal energy of the gas during the transition is

The density $\rho$ versus volume $V$ graph is shown in the figure. Find the corresponding pressure $P$ versus temperature $T$ graph.

An ideal gas undergoes a circular cycle centered at $4 \, atm, 4 \, L$ as shown in the diagram. The maximum temperature attained in this process is close to

$n$ moles of an ideal gas undergo a process $A \to B$ as shown in the figure. The maximum temperature of the gas during the process is

Vedclass Test Series

Exam Paper Generator

Online Exam Module