The n rows,each containing m cells in series, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The total number of cells is given by $m 	imes n = 24$ ... $(i)$.For maximum current in a mixed grouping of cells,the external resistance $R$ mus

Vedclass · Accepted Answer

$m = 12, n = 2$

Vedclass · Answer

(C) The total number of cells is given by $m 	imes n = 24$ ... $(i)$.For maximum current in a mixed grouping of cells,the external resistance $R$ must be equal to the equivalent internal resistance of the combination.The equivalent internal resistance is given by $R_{eq} = \frac{mr}{n}$.Given $R = 3 \,\Omega$ and $r = 0.5 \,\Omega$,we have $3 = \frac{m 	imes 0.5}{n}$.This simplifies to $3 = \frac{m}{2n}$,which gives $m = 6n$ ... $(ii)$.Substituting equation $(ii)$ into equation $(i)$: $(6n) 	imes n = 24$.$6n^2 = 24 \implies n^2 = 4 \implies n = 2$.Using $n = 2$ in equation $(ii)$,we get $m = 6 	imes 2 = 12$.Therefore,$m = 12$ and $n = 2$.

The $n$ rows,each containing $m$ cells in series,are joined in parallel. Maximum current is drawn from this combination across an external resistance of $3 \,\Omega$. If the total number of cells used is $24$ and the internal resistance of each cell is $0.5 \,\Omega$,then:

Similar Questions

Ten identical cells each emf $2 \, V$ and internal resistance $1 \, \Omega$ are connected in series with two cells wrongly connected. $A$ resistor of $10 \, \Omega$ is connected to the combination. What is the current through the resistor (in $ \, A$)?

Two cells are connected in opposition as shown. Cell $E_1$ has an electromotive force (emf) of $8 \ V$ and an internal resistance of $2 \ \Omega$; cell $E_2$ has an emf of $2 \ V$ and an internal resistance of $4 \ \Omega$. The terminal potential difference of cell $E_2$ is: (in $V$)

For a cell,the terminal potential difference $(P.D.)$ is $2.2\;V$ when the circuit is open and reduces to $1.8\;V$ when the cell is connected to an external resistance of $R = 5\;\Omega$. Determine the internal resistance $(r)$ of the cell.

Five identical cells each of internal resistance $1\, \Omega$ and $emf$ $5\, V$ are connected in series and in parallel with an external resistance $R$. For what value of $R$ will the current in the series and parallel combination remain the same? (in $\Omega$)

Two batteries with different $emf$ and different internal resistances are connected as shown in the figure. The voltage between the two terminals $A$ and $B$ is ........ $volt$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module