The V-i graph for a conductor makes an angle | vedclass

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(D) According to Ohm's Law,$V = iR$,which implies $R = V/i$.In a $V-i$ graph,the resistance $R$ is represented by the slope of the line with respect t

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$\cot 	heta$

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(D) According to Ohm's Law,$V = iR$,which implies $R = V/i$.In a $V-i$ graph,the resistance $R$ is represented by the slope of the line with respect to the $i$-axis.The slope of a line is defined as $	an(\phi)$,where $\phi$ is the angle the line makes with the $i$-axis.Given that the graph makes an angle $	heta$ with the $V$-axis,the angle it makes with the $i$-axis is $(90^\circ - 	heta)$.Therefore,the resistance $R = 	an(90^\circ - 	heta) = \cot 	heta$.

The $V-i$ graph for a conductor makes an angle $\theta$ with the $V$-axis. Here $V$ denotes the voltage and $i$ denotes the current. The resistance of the conductor is given by:

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