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(B) The reaction involves the reduction of a ketone group to a methylene group $(-CH_2-)$ in the presence of an alcohol $(-OH)$ group.Clemmensen reduc

Vedclass · Accepted Answer

Wolff-Kishner reduction

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(B) The reaction involves the reduction of a ketone group to a methylene group $(-CH_2-)$ in the presence of an alcohol $(-OH)$ group.Clemmensen reduction uses $Zn(Hg)/HCl$ (acidic medium),which would cause the dehydration or protonation of the $-OH$ group.$NaBH_4$ reduces ketones to alcohols,not to methylene groups.Wolff-Kishner reduction uses $NH_2NH_2/KOH$ (basic medium),which is suitable for this transformation as the $-OH$ group remains unaffected in basic conditions.Therefore,the correct reagent is Wolff-Kishner reduction,which corresponds to option $B$.

The above reduction can be best carried out by

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