The acceleration of an electron in the first orbit of the hydrogen atom $(Z = 1)$ is
- A$\frac{h^2}{\pi^2 m^2 r^3}$
- B$\frac{h^2}{8\pi^2 m^2 r^3}$
- C$\frac{h^2}{4\pi^2 m^2 r^3}$
- D$\frac{h^2}{4\pi m^2 r^3}$
Explore More
Similar Questions
Imagine that the electron in a hydrogen atom is replaced by a muon $(\mu)$. The mass of the muon particle is $207$ times that of an electron and its charge is equal to the charge of an electron. The ionization potential of this hydrogen atom will be ............. $eV$.
DifficultJEE MAIN 2021
View SolutionWhen an electron in a hydrogen atom jumps from the third excited state to the ground state,the de-Broglie wavelength associated with the electron becomes
An electron is revolving in $n = 3$ orbit. What will be the magnetic field at the centre of the hydrogen atom? (in $T$)
DifficultAIIMS 2019
View SolutionWhen the electron orbiting in a hydrogen atom in its ground state moves to the third excited state, the de-Broglie wavelength associated with it
The ratio of areas within the electron orbits for the first excited state to the ground state for a hydrogen atom is (in $ : 1$)
Medium
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo