The action of a nib split at the top is explained by

$A$ capillary tube of radius $r$ is immersed in water and water rises in it to a height $h$. The mass of the water in the capillary is $5 \, g$. Another capillary tube of radius $2r$ is immersed in water. The mass of water that will rise in this tube is $........ \, g$.

Water rises in a vertical capillary tube up to a height of $2.0 \, cm$. If the tube is inclined at an angle of $60^{\circ}$ with the vertical,then up to what length will the water rise in the tube?

Water rises to a height $3$ cm in a capillary tube. If the cross-sectional area of the capillary tube is reduced to $1/3^{rd}$ of its initial area, then water will rise to a height of:

This question has Statement-$I$ and Statement-$II$. Of the four choices given after the statements,choose the one that best describes the two statements.
Statement-$I$: $A$ capillary is dipped in a liquid and liquid rises to a height $h$ in it. As the temperature of the liquid is raised,the height $h$ increases (if the density of the liquid and the angle of contact remain the same).
Statement-$II$: Surface tension of a liquid decreases with the rise in its temperature.

The sap in trees,which consists mainly of water in summer,rises in a system of capillaries of radius $r = 2.5 \times 10^{-5} \ m$. The surface tension of sap is $T = 7.28 \times 10^{-2} \ N/m$ and the angle of contact is $0^{\circ}$. Does surface tension alone account for the supply of water to the top of all trees?