The action of bromine water (excess) on salic | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When salicylic acid ($2$-hydroxybenzoic acid) is treated with excess bromine water,it undergoes electrophilic aromatic substitution. The $-OH$ gro

Vedclass · Accepted Answer

Vedclass · Answer

(C) When salicylic acid ($2$-hydroxybenzoic acid) is treated with excess bromine water,it undergoes electrophilic aromatic substitution. The $-OH$ group is strongly activating and ortho/para directing,while the $-COOH$ group is deactivating. Due to the strong activation by the $-OH$ group,the bromine atoms substitute at the available ortho and para positions relative to the $-OH$ group. Additionally,the $-COOH$ group is a good leaving group in the presence of excess bromine,leading to ipso substitution where the $-COOH$ group is replaced by a $-Br$ atom. Thus,the final product is $2,4,6$-tribromophenol.

The action of bromine water (excess) on salicylic acid results in the formation of

Similar Questions

The major product in the following reaction is:

What is the product formed when salicylic acid is heated with sodalime?

Which among the following has the highest melting point?

The major product of the following reaction is:

Explain the classification of phenols with examples.

Vedclass Test Series

Exam Paper Generator

Online Exam Module