The adjoining diagram shows three soap bubble | vedclass

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(C) The excess pressure inside a soap bubble is given by $\Delta P = \frac{4T}{r}$,where $T$ is the surface tension and $r$ is the radius of the bubbl

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$C$ and $A$ both will start collapsing with the volume of $B$ increasing.

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(C) The excess pressure inside a soap bubble is given by $\Delta P = \frac{4T}{r}$,where $T$ is the surface tension and $r$ is the radius of the bubble.This means that the excess pressure is inversely proportional to the radius of the bubble,i.e.,$\Delta P \propto \frac{1}{r}$.From the diagram,it is clear that the radius of bubble $B$ is larger than the radii of bubbles $A$ and $C$ ($r_B > r_A$ and $r_B > r_C$).Therefore,the excess pressure inside $A$ and $C$ is greater than the excess pressure inside $B$.When the stop cocks $S_1, S_2$ and $S_3$ are opened,air will flow from the region of higher pressure to the region of lower pressure.Consequently,air will move from bubbles $A$ and $C$ towards bubble $B$.As a result,bubbles $A$ and $C$ will start collapsing (their volumes will decrease),and bubble $B$ will start expanding (its volume will increase).

The adjoining diagram shows three soap bubbles $A, B$ and $C$ prepared by blowing the capillary tube fitted with stop cocks $S_1, S_2$ and $S_3$. With stop cock $S$ closed and stop cocks $S_1, S_2$ and $S_3$ opened,what will happen?

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