The ammonia evolved from the treatment of 0.3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. Calculate the milliequivalents of $H_2SO_4$ taken: $100 \, mL 	imes 0.1 \, M 	imes 2 \, (	ext{basicity}) = 20 \, meq$. $2$. Calculate the

Vedclass · Accepted Answer

Urea

Vedclass · Answer

(A) $1$. Calculate the milliequivalents of $H_2SO_4$ taken: $100 \, mL 	imes 0.1 \, M 	imes 2 \, (	ext{basicity}) = 20 \, meq$. $2$. Calculate the milliequivalents of $NaOH$ used for back titration: $20 \, mL 	imes 0.5 \, M 	imes 1 \, (	ext{acidity}) = 10 \, meq$. $3$. Milliequivalents of $NH_3$ evolved = $20 - 10 = 10 \, meq = 0.01 \, eq$. $4$. Percentage of nitrogen = $\frac{1.4 	imes 	ext{meq of } NH_3}{	ext{mass of compound}} = \frac{1.4 	imes 10}{0.30} = 46.66 \%$. $5$. Nitrogen percentage in Urea $(NH_2)_2CO$: $\frac{28}{60} 	imes 100 = 46.66 \%$. $6$. Since the percentage matches,the compound is Urea.

The ammonia evolved from the treatment of $0.30 \, g$ of an organic compound for the estimation of nitrogen was passed in $100 \, mL$ of $0.1 \, M$ sulphuric acid. The excess of acid required $20 \, mL$ of $0.5 \, M$ sodium hydroxide solution for complete neutralization. The organic compound is:

Similar Questions

$100 \ mL$ of aqueous solution of $0.05 \ M$ $Cu^{2+}$ is added to $1 \ L$ of $0.1 \ M$ $KI$ solution. The resultant solution was titrated with $0.01 \ M$ $Na_2S_2O_3$ solution using starch indicator till blue color disappeared. What is the volume (in $mL$) of $Na_2S_2O_3$ used?

Which of the following reagents is not used in qualitative and quantitative chemical analysis?

Iodine and hypo react to produce

Why is it essential to wash the precipitate with water before estimating it quantitatively?

During the preparation of Mohr's salt solution (Ferrous ammonium sulphate),which of the following acid is added to prevent hydrolysis of $Fe^{2+}$ ion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module