(C) The number of half-lives $(n)$ is calculated as: $n = \frac{\text{Total time}}{t_{1/2}} = \frac{50 \ minutes}{25 \ minutes} = 2$.The fraction of t

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(C) The number of half-lives $(n)$ is calculated as: $n = \frac{\text{Total time}}{t_{1/2}} = \frac{50 \ minutes}{25 \ minutes} = 2$.The fraction of the substance remaining is given by the formula: $\text{Amount left} = (1/2)^n$.Substituting the value of $n$: $\text{Amount left} = (1/2)^2 = 1/4$ (One-fourth).

Class 12 Chemistry Nuclear Chemistry Rate of decay and Half-life

Medium

The amount of $_{53}I^{128}$ $(t_{1/2} = 25 \ minutes)$ left after $50 \ minutes$ will be

AIIMS 1982 All AIIMS

A
One-half
B
One-third
C
One-fourth
D
Nothing

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The amount of $_{53}I^{128}$ $(t_{1/2} = 25 \ minutes)$ left after $50 \ minutes$ will be

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