Calculate the amount of heat liberated in the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Before closing the switch $S$,the potential difference across both capacitors is $V$. The left capacitor is connected to a battery of potential $V

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(A) Before closing the switch $S$,the potential difference across both capacitors is $V$. The left capacitor is connected to a battery of potential $V$,and the right capacitor is connected to another battery of potential $V$. When the switch $S$ is closed,the potential difference across both capacitors remains $V$ because they are connected in parallel to their respective batteries. Since there is no change in the potential difference across the capacitors,there is no redistribution of charge. Therefore,the change in the energy of the system is zero,and the heat liberated in the circuit is $H = 0$.

Calculate the amount of heat liberated in the circuit after closing the switch $S$.

Similar Questions

At distances of $5 \ cm$ and $10 \ cm$ outwards from the surface of a uniformly charged solid sphere,the potentials are $100 \ V$ and $75 \ V$ respectively. Then:

The diagram shows four capacitors with capacitances and breakdown voltages as mentioned. What should be the maximum value of the external emf source such that no capacitor breaks down? (in $kV$)

Assuming the drops to be spherical,$27$ identical drops of mercury are charged simultaneously to the same potential of $20 \ V$. If all the charged drops are made to combine to form one big drop,then the potential of the big drop will be: (in $V$)

In the network shown below,the charge accumulated in the capacitor in steady state will be ........... $\mu C$.

Each plate of a parallel plate capacitor has a charge $q$ on it. The capacitor is now connected to a battery. Now,

Vedclass Test Series

Exam Paper Generator

Online Exam Module