The amount of silver deposited by passing 241 | vedclass

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(C) According to Faraday's first law of electrolysis,the mass of substance deposited is given by $m = Z 	imes Q$,where $Z$ is the electrochemical equ

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$0.27 \ g$

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(C) According to Faraday's first law of electrolysis,the mass of substance deposited is given by $m = Z 	imes Q$,where $Z$ is the electrochemical equivalent and $Q$ is the charge in Coulombs.The electrochemical equivalent of silver $(Ag)$ is approximately $1.118 	imes 10^{-3} \ g/C$.Given,$Q = 241.25 \ C$.Therefore,the mass of silver deposited is $m = 1.118 	imes 10^{-3} \ g/C 	imes 241.25 \ C$.$m \approx 0.2697 \ g \approx 0.27 \ g$.

The amount of silver deposited by passing $241.25 \ C$ of charge through a silver nitrate solution is

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