The amplification factor of a triode is 20,th | vedclass

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(A) Given:Amplification factor $\mu = 20$Trans-conductance $g_m = 3 	ext{ mS} = 3 	imes 10^{-3} \ \Omega^{-1}$Load resistance $R_L = 3 	imes 10^4 \

Vedclass · Accepted Answer

$16.36$

Vedclass · Answer

(A) Given:Amplification factor $\mu = 20$Trans-conductance $g_m = 3 	ext{ mS} = 3 	imes 10^{-3} \ \Omega^{-1}$Load resistance $R_L = 3 	imes 10^4 \ \Omega$First,we find the plate resistance $r_p$ using the relation $\mu = g_m 	imes r_p$:$r_p = \frac{\mu}{g_m} = \frac{20}{3 	imes 10^{-3}} = \frac{20000}{3} \ \Omega$The formula for voltage gain $A_v$ is:$A_v = \frac{\mu 	imes R_L}{r_p + R_L}$Substituting the values:$A_v = \frac{20 	imes 3 	imes 10^4}{\frac{20000}{3} + 30000}$$A_v = \frac{600000}{\frac{20000 + 90000}{3}} = \frac{600000 	imes 3}{110000}$$A_v = \frac{180}{11} \approx 16.36$

The amplification factor of a triode is $20$,the trans-conductance is $3 \text{ mS}$ (milli mho),and the load resistance is $3 \times 10^4 \ \Omega$. Calculate the voltage gain.

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