The amplitude of 15 sin (1000 pi t) is modula | vedclass

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(D) The carrier wave is given by $c(t) = 15 \sin(1000 \pi t)$.The carrier frequency $f_c$ is calculated as $f_c = \frac{\omega_c}{2\pi} = \frac{1000\p

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$(1), (4)$ and $(5)$ only

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(D) The carrier wave is given by $c(t) = 15 \sin(1000 \pi t)$.The carrier frequency $f_c$ is calculated as $f_c = \frac{\omega_c}{2\pi} = \frac{1000\pi}{2\pi} = 500\,Hz$.The modulating signal is given by $m(t) = 10 \sin(4 \pi t)$.The modulating frequency $f_m$ is calculated as $f_m = \frac{\omega_m}{2\pi} = \frac{4\pi}{2\pi} = 2\,Hz$.An amplitude modulated $(AM)$ wave contains the carrier frequency and two sideband frequencies: $(f_c - f_m)$ and $(f_c + f_m)$.Sideband frequencies are $(500 - 2)\,Hz = 498\,Hz$ and $(500 + 2)\,Hz = 502\,Hz$.Therefore,the frequencies present in the $AM$ signal are $500\,Hz, 498\,Hz,$ and $502\,Hz$,which correspond to items $(1), (4),$ and $(5)$.

The amplitude of $15 \sin (1000 \pi t)$ is modulated by $10 \sin (4 \pi t)$ signal. The amplitude modulated signal contains frequencies of
$1. 500\,Hz$
$2. 2\,Hz$
$3. 250\,Hz$
$4. 498\,Hz$
$5. 502\,Hz$
Choose the correct answer from the options given below:

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The amplitude of $15 \sin (1000 \pi t)$ is modulated by $10 \sin (4 \pi t)$ signal. The amplitude modulated signal contains frequencies of$1. 500\,Hz$$2. 2\,Hz$$3. 250\,Hz$$4. 498\,Hz$$5. 502\,Hz$Choose the correct answer from the options given below: