The angle between the minute hand and the hou | vedclass

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(B) The angle traced by the hour hand in $10$ hours and $30$ minutes ($10.5$ hours) is calculated as follows:Since the hour hand moves $360^{\circ}$ i

Vedclass · Accepted Answer

$135$

Vedclass · Answer

(B) The angle traced by the hour hand in $10$ hours and $30$ minutes ($10.5$ hours) is calculated as follows:Since the hour hand moves $360^{\circ}$ in $12$ hours,it moves $\frac{360^{\circ}}{12} = 30^{\circ}$ per hour.For $10.5$ hours,the angle is $10.5 	imes 30^{\circ} = 315^{\circ}$.The angle traced by the minute hand in $30$ minutes is calculated as follows:Since the minute hand moves $360^{\circ}$ in $60$ minutes,it moves $\frac{360^{\circ}}{60} = 6^{\circ}$ per minute.For $30$ minutes,the angle is $30 	imes 6^{\circ} = 180^{\circ}$.The required angle between the hands is the difference between these two angles:$	ext{Angle} = |315^{\circ} - 180^{\circ}| = 135^{\circ}$.

The angle between the $minute$ hand and the $hour$ hand of a clock when the time is $10.30$ is (in $^{\circ}$)

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