The angle of dip at a place is 40.6^circ and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The vertical component of the earth's magnetic field is given by the formula: $V = I \sin \phi$,where $I$ is the total intensity and $\phi$ is the

Vedclass · Accepted Answer

$9.2 	imes 10^{-5} 	ext{ Tesla}$

Vedclass · Answer

(D) The vertical component of the earth's magnetic field is given by the formula: $V = I \sin \phi$,where $I$ is the total intensity and $\phi$ is the angle of dip.Given: $V = 6 	imes 10^{-5} 	ext{ Tesla}$ and $\phi = 40.6^\circ$.Rearranging the formula to solve for $I$: $I = \frac{V}{\sin \phi}$.Substituting the values: $I = \frac{6 	imes 10^{-5}}{\sin 40.6^\circ}$.Using $\sin 40.6^\circ \approx 0.65$,we get: $I = \frac{6 	imes 10^{-5}}{0.65} \approx 9.23 	imes 10^{-5} 	ext{ Tesla}$.Thus,the total intensity is approximately $9.2 	imes 10^{-5} 	ext{ Tesla}$.

The angle of dip at a place is $40.6^\circ$ and the intensity of the vertical component of the earth's magnetic field $V = 6 \times 10^{-5} \text{ Tesla}$. The total intensity of the earth's magnetic field $(I)$ at this place is:

Similar Questions

The value of horizontal component of earth's magnetic field at a place is $0.35 \times 10^{-4} \,T$. If the angle of dip is $60^{\circ}$,the value of vertical component of earth's magnetic field is nearly ............. $\times 10^{-4} \,T$.

At a certain place,the horizontal component of the Earth's magnetic field is $B_0$ and the angle of dip is $45^o$. The total intensity of the Earth's magnetic field at that place will be:

$A$ small bar magnet $A$ oscillates in a horizontal plane with a period $T$ at a place where the angle of dip is $60^o$. When the same needle is made to oscillate in a vertical plane coinciding with the magnetic meridian,its period will be

$A$ compass needle oscillates $20$ times per minute at a place where the dip is $30^{\circ}$ and $30$ times per minute where the dip is $60^{\circ}$. The ratio of total magnetic field due to the earth at the two places respectively is $\frac{4}{\sqrt{x}}$. The value of $x$ is $............$.

At the magnetic north pole of the earth, the value of the horizontal component of the earth's magnetic field and the angle of dip are, respectively:

Vedclass Test Series

Exam Paper Generator

Online Exam Module