The angle of elevation of a tower from a distance of $100 \ m$ from its foot is $30^{\circ}$. Then the height of the tower is (in $m$):
- A$100 \sqrt{3}$
- B$\frac{50}{\sqrt{3}}$
- C$50 \sqrt{3}$
- D$\frac{100}{\sqrt{3}}$
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