The angle of elevation of the top of a $TV$ tower from three points $A, B, C$ in a straight line through the foot of the tower are $\alpha, 2 \alpha, 3 \alpha$ respectively. If $AB = a$,the height of the tower is

  • A
    $a \tan \alpha$
  • B
    $a \sin \alpha$
  • C
    $a \sin 2 \alpha$
  • D
    $a \sin 3 \alpha$

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