The angle strain in cyclopropane is:

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Question

(A) The bond angle in cyclopropane is calculated as $	heta = \frac{180(n-2)}{n} = \frac{180(3-2)}{3} = 60^{\circ}$.Angle strain is defined as $\alpha

Vedclass · Accepted Answer

$24^{\circ} 44^{\prime}$

Vedclass · Answer

(A) The bond angle in cyclopropane is calculated as $	heta = \frac{180(n-2)}{n} = \frac{180(3-2)}{3} = 60^{\circ}$.Angle strain is defined as $\alpha = \frac{1}{2} (109^{\circ} 28^{\prime} - 	heta)$.Substituting the value of $	heta = 60^{\circ}$:$\alpha = \frac{1}{2} (109^{\circ} 28^{\prime} - 60^{\circ}) = \frac{1}{2} (49^{\circ} 28^{\prime}) = 24^{\circ} 44^{\prime}$.

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