The angles $A, B$ and $C$ of a triangle $ABC$ are in $A.P.$ and $a : b = 1 : \sqrt{3}$. If $c = 4 \text{ cm}$,then the area (in $\text{sq. cm}$) of this triangle is:

  • A
    $2\sqrt{3}$
  • B
    $\frac{4}{\sqrt{3}}$
  • C
    $4\sqrt{3}$
  • D
    $\frac{2}{\sqrt{3}}$

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