Difficult
The angular momentum of an electron in a $d$ orbital is equal to:
- A$2 \sqrt{3} \ \hbar$
- B$0 \ \hbar$
- C$\sqrt{6} \ \hbar$
- D$\sqrt{2} \ \hbar$
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Similar Questions
Match the columns and choose the correct option:
Column-$I$ Column-$II$ $(a)$ $4s$ $(p)$ Circular orbit around nucleus $(b)$ $4p$ $(q)$ Non-directional orbital $(c)$ $1s$ $(r)$ Angular momentum $= 2h/\pi$ $(d)$ $3d$ $(s)$ Radial node is zero
| Column-$I$ | Column-$II$ |
|---|---|
| $(a)$ $4s$ | $(p)$ Circular orbit around nucleus |
| $(b)$ $4p$ | $(q)$ Non-directional orbital |
| $(c)$ $1s$ | $(r)$ Angular momentum $= 2h/\pi$ |
| $(d)$ $3d$ | $(s)$ Radial node is zero |
Medium
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View SolutionWhat is the atomic number of an element whose $M^{2+}$ ion has the electronic configuration $[Ar] \, 3d^8$?
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View SolutionAn orbital with one angular node shows three maxima in its radial probability distribution curve, the orbital is
The $d$ orbital with the orientation along $X$ and $Y$ axis is called.
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