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(B) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{th}$ orbit is given by:$L = \frac{nh}{2\pi}$This implies that $L

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$\frac{4}{3} l$

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(B) According to Bohr's postulate,the angular momentum $L$ of an electron in the $n^{th}$ orbit is given by:$L = \frac{nh}{2\pi}$This implies that $L \propto n$.For the third Bohr orbit $(n_1 = 3)$,the angular momentum is $L_1 = l$.For the fourth Bohr orbit $(n_2 = 4)$,let the angular momentum be $L_2 = L'$.Using the proportionality $L \propto n$,we have:$\frac{L_1}{L_2} = \frac{n_1}{n_2}$$\frac{l}{L'} = \frac{3}{4}$$L' = \frac{4}{3} l$

The angular momentum of the electron in the third Bohr orbit of hydrogen atom is $l$. Its angular momentum in the fourth Bohr orbit is

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