The approximate wavelength of a photon of ene | vedclass

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.For energy in $eV$ and wavelength in $\mathring A$,the relation is approxi

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$5000$

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(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.For energy in $eV$ and wavelength in $\mathring A$,the relation is approximately $E(eV) = \frac{12400}{\lambda(\mathring A)}$.Given $E = 2.48 \,eV$,we have $2.48 = \frac{12400}{\lambda}$.$\lambda = \frac{12400}{2.48} \, \mathring A$.$\lambda = 5000 \, \mathring A$.Thus,the approximate wavelength is $5000 \, \mathring A$.

The approximate wavelength of a photon of energy $2.48 \,eV$ is ............ $\mathring A$.

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