(A) The area of the circle $\odot(O, r)$ is given as $\pi r^2 = 240 \, cm^2$.The formula for the area of a sector with central angle $\theta$ is $\tex

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(A) The area of the circle $\odot(O, r)$ is given as $\pi r^2 = 240 \, cm^2$.The formula for the area of a sector with central angle $\theta$ is $\text{Area} = \frac{\theta}{360^\circ} \times \pi r^2$.Given $\theta = 45^\circ$ and $\pi r^2 = 240 \, cm^2$,we substitute these values into the formula:$\text{Area of minor sector } OACB = \frac{45}{360} \times 240$$\text{Area of minor sector } OACB = \frac{1}{8} \times 240 = 30 \, cm^2$.Therefore,the area of the minor sector is $30 \, cm^2$.

Class 10 Mathematics Areas Related to Circles Areas of Sector and Segment of a Circle

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The area of $\odot(O, r)$ is $240 \, cm^2$. In $\odot(O, r)$,minor arc $\widehat{ACB}$ subtends an angle of measure $45^\circ$ at the centre. Then,the area of minor sector $OACB$ is $\dots \dots \dots \, cm^2$.

A
$30$
B
$40$
C
$60$
D
$80$

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Areas Related to Circles

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Areas of Sector and Segment of a Circle

The radii of two circles are $19\, cm$ and $9\, cm$ respectively. Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles. (in $cm$) [use $\pi=\frac{22}{7}$]

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Area of a circle is $5544 \, cm^{2}$. Find its radius (in $cm$).

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In a circle with radius $14 \, cm$,the area of the minor sector corresponding to minor $\widehat{ACB}$ is $77 \, cm^2$. Then,minor $\widehat{ACB}$ subtends an angle of measure $\dots$ at the centre. (in $^\circ$)

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In a circle,the ratio of the areas of two distinct minor sectors is $1:4$. Then,the ratio of the angles at the centre for those minor sectors is $\ldots \ldots \ldots \ldots$.

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In a circle with radius $42 \ cm$,a minor arc subtends an angle of $60^{\circ}$ at the centre. Find the area of the minor sector and the minor segment corresponding to this arc. (Use $\sqrt{3} = 1.73$)

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The area of $\odot(O, r)$ is $240 \, cm^2$. In $\odot(O, r)$,minor arc $\widehat{ACB}$ subtends an angle of measure $45^\circ$ at the centre. Then,the area of minor sector $OACB$ is $\dots \dots \dots \, cm^2$.

Similar Questions

The radii of two circles are $19\, cm$ and $9\, cm$ respectively. Find the radius of the circle which has circumference equal to the sum of the circumferences of the two circles. (in $cm$) [use $\pi=\frac{22}{7}$]

Area of a circle is $5544 \, cm^{2}$. Find its radius (in $cm$).

In a circle with radius $14 \, cm$,the area of the minor sector corresponding to minor $\widehat{ACB}$ is $77 \, cm^2$. Then,minor $\widehat{ACB}$ subtends an angle of measure $\dots$ at the centre. (in $^\circ$)

In a circle,the ratio of the areas of two distinct minor sectors is $1:4$. Then,the ratio of the angles at the centre for those minor sectors is $\ldots \ldots \ldots \ldots$.

In a circle with radius $42 \ cm$,a minor arc subtends an angle of $60^{\circ}$ at the centre. Find the area of the minor sector and the minor segment corresponding to this arc. (Use $\sqrt{3} = 1.73$)

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