The area of the region bounded by the curve $xy = 4$,$x = 1$,and $x = 3$ is . . . . . . sq. units.

  • A
    $4 \log 3$
  • B
    $4 \log 2$
  • C
    $4 \log 4$
  • D
    $4 \log 6$

Explore More

Similar Questions

Find the area enclosed by the ellipse $\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1$.

Difficult
View Solution

The area (in sq units) of the region bounded by $x=-1$, $x=2$, $y=x^2+1$ and $y=2x-2$ is

If $y = 2 \sin x + \sin 2x$ for $0 \le x \le 2 \pi ,$ then the area enclosed by the curve and the $x-$axis is

Area enclosed by the ellipse $\frac{x^2}{16} + \frac{y^2}{9} = 1$ is . . . . . . .

The area bounded by the curve $x=4-y^2$ and the $Y$-axis is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo