The area of the region bounded by the curve y | vedclass

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(B) The required area is given by the integral of the function $y = 	an x$ from $x = 0$ to $x = \frac{\pi}{3}$.$	ext{Required area} = \int_0^{\pi /

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$\log 2$

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(B) The required area is given by the integral of the function $y = 	an x$ from $x = 0$ to $x = \frac{\pi}{3}$.$	ext{Required area} = \int_0^{\pi / 3} 	an x \, dx$We know that the integral of $	an x$ is $\log |\sec x|$.$	ext{Required area} = [\log |\sec x|]_0^{\pi / 3}$Now,substitute the limits:$= \log |\sec \frac{\pi}{3}| - \log |\sec 0|$Since $\sec \frac{\pi}{3} = 2$ and $\sec 0 = 1$:$= \log |2| - \log |1|$$= \log 2 - 0 = \log 2 	ext{ sq units}$.

The area of the region bounded by the curve $y = \tan x$,the $X$-axis,and the line $x = \frac{\pi}{3}$ is

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