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(A) The given pair of lines are $xy = 0$ and $xy + 5x - 4y - 20 = 0$.From $xy = 0$,we get the lines $x = 0$ (y-axis) and $y = 0$ (x-axis).From the sec

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$20$ square units

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(A) The given pair of lines are $xy = 0$ and $xy + 5x - 4y - 20 = 0$.From $xy = 0$,we get the lines $x = 0$ (y-axis) and $y = 0$ (x-axis).From the second equation,$xy + 5x - 4y - 20 = 0$,we can factorize it as:$x(y + 5) - 4(y + 5) = 0$$(x - 4)(y + 5) = 0$This gives the lines $x = 4$ and $y = -5$.The region is bounded by the lines $x = 0$,$x = 4$,$y = 0$,and $y = -5$.This forms a rectangle with length $|4 - 0| = 4$ units and width $|0 - (-5)| = 5$ units.The area of the rectangle is $	ext{length} 	imes 	ext{width} = 4 	imes 5 = 20$ square units.

The area of the region enclosed between the pair of lines $xy = 0$ and the lines $xy + 5x - 4y - 20 = 0$ is .....

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