The area of a triangle having vertices A(0,0) | vedclass

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(A) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2)$ and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(A) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2)$ and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Given vertices are $A(0,0), B(4,0)$ and $C(0,6)$.Substituting these values into the formula:Area $= \frac{1}{2} |0(0 - 6) + 4(6 - 0) + 0(0 - 0)|$Area $= \frac{1}{2} |0 + 24 + 0|$Area $= \frac{1}{2} |24| = 12$ square units.

The area of a triangle having vertices $A(0,0), B(4,0)$ and $C(0,6)$ is:

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