The ascending order of acidity of the -OH gro | vedclass

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(A) The acidity of phenols depends on the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(-EWG)$ incre

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$A < C < D < B < E$

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(A) The acidity of phenols depends on the stability of the phenoxide ion formed after the loss of a proton. Electron-withdrawing groups $(-EWG)$ increase acidity by stabilizing the negative charge,while electron-donating groups $(-EDG)$ decrease acidity by destabilizing it.$1$. $E$ ($2,4$-dinitrophenol): Has two $-NO_2$ groups (strong $-M$ and $-I$ effect),making it the most acidic.$2$. $B$ ($p$-nitrophenol): Has one $-NO_2$ group ($-M$ and $-I$ effect),making it more acidic than phenol.$3$. $D$ (Phenol): The reference compound.$4$. $C$ ($p$-methoxyphenol): The $-OCH_3$ group has a $+M$ effect,which destabilizes the phenoxide ion,making it less acidic than phenol.$5$. $A$ $(Bu-OH)$: Aliphatic alcohols are significantly less acidic than phenols because the alkoxide ion is not resonance-stabilized.Thus,the order of acidity is: $A < C < D < B < E$.

The ascending order of acidity of the $-OH$ group in the following compounds is:
$A$. $Bu-OH$
$B$. $p$-nitrophenol
$C$. $p$-methoxyphenol
$D$. Phenol
$E$. $2,4$-dinitrophenol
Choose the correct answer from the options given below:

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The ascending order of acidity of the $-OH$ group in the following compounds is:$A$. $Bu-OH$$B$. $p$-nitrophenol$C$. $p$-methoxyphenol$D$. Phenol$E$. $2,4$-dinitrophenolChoose the correct answer from the options given below: