The audio signal used to modulate 60 sin(2pi | vedclass

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(C) The carrier wave is given by $E_c(t) = 60 \sin(2\pi 	imes 10^6 t)$,so the amplitude of the carrier wave is $E_c = 60$.The modulating signal is gi

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$25$

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(C) The carrier wave is given by $E_c(t) = 60 \sin(2\pi 	imes 10^6 t)$,so the amplitude of the carrier wave is $E_c = 60$.The modulating signal is given by $E_m(t) = 15 \sin(300\pi t)$,so the amplitude of the modulating signal is $E_m = 15$.The modulation index (or depth of modulation) $m_a$ is defined as the ratio of the amplitude of the modulating signal to the amplitude of the carrier wave:$m_a = \frac{E_m}{E_c} = \frac{15}{60} = 0.25$.To express this as a percentage,we multiply by $100$:$m_a = 0.25 	imes 100 = 25\%$.

List-$I$	List-$II$
$A$. $AM$ Broadcast	$I$. $88-108\,MHz$
$B$. $FM$ Broadcast	$II$. $540-1600\,kHz$
$C$. Television	$III$. $3.7-4.2\,GHz$
$D$. Satellite Communication	$IV$. $54-890\,MHz$

$List-I$	$List-II$
$A.$ Facsimile	$I.$ Static Document Image
$B.$ Guided media Channel	$II.$ Local Broadcast Radio
$C.$ Frequency Modulation	$III.$ Rectangular wave
$D.$ Digital Signal	$IV.$ Optical Fiber

The audio signal used to modulate $60 \sin(2\pi \times 10^6 t)$ is $15 \sin(300\pi t)$. The depth of modulation is.......$\%$

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Match List-$I$ with List-$II$:

List-$I$ List-$II$

$A$. $AM$ Broadcast $I$. $88-108\,MHz$

$B$. $FM$ Broadcast $II$. $540-1600\,kHz$

$C$. Television $III$. $3.7-4.2\,GHz$

$D$. Satellite Communication $IV$. $54-890\,MHz$

Choose the correct answer from the options given below:

$List-I$ $List-II$
$A.$ Facsimile $I.$ Static Document Image
$B.$ Guided media Channel $II.$ Local Broadcast Radio
$C.$ Frequency Modulation $III.$ Rectangular wave
$D.$ Digital Signal $IV.$ Optical Fiber
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