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(A) Let the ages of mother,father,and son at the time of marriage be $M, F,$ and $S$ respectively.Given,$(M + F + S) / 3 = 42$,so $M + F + S = 126$.Le

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$25$

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(A) Let the ages of mother,father,and son at the time of marriage be $M, F,$ and $S$ respectively.Given,$(M + F + S) / 3 = 42$,so $M + F + S = 126$.Let the bride's age at the time of marriage be $B$.After $6$ years,the ages of mother,father,son,and bride will be $(M+6), (F+6), (S+6),$ and $(B+6)$ respectively.An infant was born $1$ year after the marriage,so the infant's age after $6$ years of marriage is $6 - 1 = 5$ years.The total number of family members is $5$ (mother,father,son,bride,and infant).The average age after $6$ years is $36$,so the total age is $36 	imes 5 = 180$.Equation: $(M+6) + (F+6) + (S+6) + (B+6) + 5 = 180$.$(M + F + S) + 18 + B + 6 + 5 = 180$.$126 + 29 + B = 180$.$155 + B = 180$.$B = 180 - 155 = 25$ years.

The average age of mother,father,and son was $42$ years at the time of the son's marriage. After one year,an infant was born in the family,and after $6$ years of marriage,the average age of the family is $36$ years. What was the age of the bride at the time of marriage in years?

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