The average kinetic energy of thermal neutron | vedclass

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Question

(A) Thermal neutrons are neutrons that are in thermal equilibrium with their surroundings,typically at room temperature $(T \approx 300 	ext{ K})$.Th

Vedclass · Accepted Answer

$0.03 	ext{ eV}$

Vedclass · Answer

(A) Thermal neutrons are neutrons that are in thermal equilibrium with their surroundings,typically at room temperature $(T \approx 300 	ext{ K})$.The average kinetic energy $(E_{avg})$ of a particle in thermal equilibrium is given by the formula:$E_{avg} = \frac{3}{2} K_B T$Given:$K_B = 8 	imes 10^{-5} 	ext{ eV/K}$$T = 300 	ext{ K}$Substituting the values:$E_{avg} = \frac{3}{2} 	imes (8 	imes 10^{-5} 	ext{ eV/K}) 	imes 300 	ext{ K}$$E_{avg} = 1.5 	imes 2400 	imes 10^{-5} 	ext{ eV}$$E_{avg} = 3600 	imes 10^{-5} 	ext{ eV}$$E_{avg} = 0.036 	ext{ eV}$This value is of the order of $0.03 	ext{ eV}$.Therefore,the correct option is $A$.

The average kinetic energy of thermal neutrons is of the order of (Boltzmann's constant $K_B = 8 \times 10^{-5} \text{ eV/K}$ and room temperature $T \approx 300 \text{ K}$)

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