The average speed of a cyclist who covers the | vedclass

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Question

(D) The average speed is defined as the total distance covered divided by the total time taken.Total distance $= 1 + 1 + 1 = 3 \, km$.Time taken for t

Vedclass · Accepted Answer

$15.32$

Vedclass · Answer

(D) The average speed is defined as the total distance covered divided by the total time taken.Total distance $= 1 + 1 + 1 = 3 \, km$.Time taken for the first km $(t_1)$ $= \frac{1}{20} \, hr$.Time taken for the second km $(t_2)$ $= \frac{1}{16} \, hr$.Time taken for the third km $(t_3)$ $= \frac{1}{12} \, hr$.Total time $(T)$ $= t_1 + t_2 + t_3 = \frac{1}{20} + \frac{1}{16} + \frac{1}{12}$.Taking the least common multiple $(LCM)$ of $20, 16,$ and $12$,which is $240$:$T = \frac{12 + 15 + 20}{240} = \frac{47}{240} \, hr$.Average speed $= \frac{	ext{Total distance}}{	ext{Total time}} = \frac{3}{47/240} = \frac{3 	imes 240}{47} = \frac{720}{47} \approx 15.32 \, km/hr$.

The average speed of a cyclist who covers the first,second,and third km at $20, 16,$ and $12 \, km/hr$ respectively (in $km/hr$) is:

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