The average translational kinetic energy of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The average translational kinetic energy of a gas molecule is given by the formula $E = \frac{3}{2} k T$,where $k$ is the Boltzmann constant and $

Vedclass · Accepted Answer

$5060$

Vedclass · Answer

(D) The average translational kinetic energy of a gas molecule is given by the formula $E = \frac{3}{2} k T$,where $k$ is the Boltzmann constant and $T$ is the absolute temperature in Kelvin.Given,$E = 0.69 \ eV = 0.69 	imes 1.6 	imes 10^{-19} \ J$.Substituting the values into the formula:$0.69 	imes 1.6 	imes 10^{-19} = \frac{3}{2} 	imes 1.38 	imes 10^{-23} 	imes T$$T = \frac{0.69 	imes 1.6 	imes 10^{-19} 	imes 2}{3 	imes 1.38 	imes 10^{-23}}$$T = \frac{2.208 	imes 10^{-19}}{4.14 	imes 10^{-23}} \approx 5333 \ K$To convert the temperature to Celsius,we use $T(^{\circ}C) = T(K) - 273.15$.$T(^{\circ}C) = 5333 - 273 = 5060^{\circ} C$.Therefore,the correct option is $D$.

The average translational kinetic energy of a molecule in a gas becomes equal to $0.69 \ eV$ at a temperature of about,[Boltzmann's constant $= 1.38 \times 10^{-23} \ J \ K^{-1}$] (in $^{\circ} C$)

Similar Questions

Write the kinetic interpretation of temperature.

If the average kinetic energy of a gas molecule at $27^{\circ} C$ is $3.3 \times 10^{-20} \,J$, then the average kinetic energy of the gas molecules at $127^{\circ} C$ is

At $27^{\circ} C$ temperature,the mean kinetic energy of the atoms of an ideal gas is $E_1$. If the temperature is increased to $327^{\circ} C$,then the mean kinetic energy of the atoms will be

$A$ cylinder has a capacity of $20 \, L$ and is filled with $H_2$ gas. The total average kinetic energy of the gas is $1.5 \times 10^5 \, J$. What is the pressure of the hydrogen gas?

The mean kinetic energy of the molecules of an ideal gas at $399^{\circ} C$ is $E$. The temperature at which the mean kinetic energy of its molecules will be $E/2$ is: (in $^{\circ} C$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module