The average value of the numbers 15, 21, 32, | vedclass

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Question

(A) The sum of the given numbers is $15 + 21 + 32 + 35 + 46 + x + 59 + 65 + 72 = 345 + x$.There are $9$ numbers in total.The average is given by $\fra

Vedclass · Accepted Answer

$42 \leq x \leq 51$

Vedclass · Answer

(A) The sum of the given numbers is $15 + 21 + 32 + 35 + 46 + x + 59 + 65 + 72 = 345 + x$.There are $9$ numbers in total.The average is given by $\frac{345 + x}{9}$.According to the problem,$43 \leq \frac{345 + x}{9} \leq 44$.Multiplying the entire inequality by $9$,we get $387 \leq 345 + x \leq 396$.Subtracting $345$ from all parts of the inequality,we get $387 - 345 \leq x \leq 396 - 345$.Thus,$42 \leq x \leq 51$.

The average value of the numbers $15, 21, 32, 35, 46, x, 59, 65, 72$ should be greater than or equal to $43$ but less than or equal to $44$. Then the value of $x$ should be

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