The average weight of 3 men A, B and C is 84 | vedclass

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(C) $1$. The sum of weights of $A, B, C$ is $84 	imes 3 = 252 \, kg$.$2$. When $D$ joins,the total weight of $A, B, C, D$ is $80 	imes 4 = 320 \, kg

Vedclass · Accepted Answer

$75$

Vedclass · Answer

(C) $1$. The sum of weights of $A, B, C$ is $84 	imes 3 = 252 \, kg$.$2$. When $D$ joins,the total weight of $A, B, C, D$ is $80 	imes 4 = 320 \, kg$.$3$. Weight of $D = 320 - 252 = 68 \, kg$.$4$. Weight of $E = 68 + 3 = 71 \, kg$.$5$. The average weight of $B, C, D, E$ is $79 \, kg$,so the sum of their weights is $79 	imes 4 = 316 \, kg$.$6$. Sum of weights of $B, C = 316 - (D + E) = 316 - (68 + 71) = 316 - 139 = 177 \, kg$.$7$. Since $A + B + C = 252 \, kg$,then $A = 252 - (B + C) = 252 - 177 = 75 \, kg$.

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