The balancing length for a cell is 560 , cm i | vedclass

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(C) In a potentiometer experiment, the balancing length $l_1$ is proportional to the electromotive force $(E)$ of the cell: $E = k l_1$, where $k$ is

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$1.2$

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(C) In a potentiometer experiment, the balancing length $l_1$ is proportional to the electromotive force $(E)$ of the cell: $E = k l_1$, where $k$ is the potential gradient. When an external resistance $R$ is connected in parallel, the terminal voltage $V$ is given by $V = E - Ir = E \left( \frac{R}{R+r} ight) = k l_2$. Given $l_1 = 560 \, cm$ and $l_2 = 560 \, cm - 60 \, cm = 500 \, cm$. The formula for internal resistance $r$ is $r = R \left( \frac{l_1 - l_2}{l_2} ight)$. Substituting the values: $r = 10 \, \Omega 	imes \left( \frac{560 - 500}{500} ight)$. $r = 10 	imes \left( \frac{60}{500} ight) = 10 	imes 0.12 = 1.2 \, \Omega$.

The balancing length for a cell is $560 \, cm$ in a potentiometer experiment. When an external resistance of $10 \, \Omega$ is connected in parallel to the cell, the balancing length changes by $60 \, cm$. The internal resistance of the cell in ohms, is

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