The base of a cone with radius 7, cm and heig | vedclass

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(A) Given: Radius $(r)$ = $7\, cm$,Height $(h)$ = $24\, cm$.First,find the slant height $(l)$ of the cone: $l = \sqrt{r^2 + h^2} = \sqrt{7^2 + 24^2} =

Vedclass · Accepted Answer

$1716$

Vedclass · Answer

(A) Given: Radius $(r)$ = $7\, cm$,Height $(h)$ = $24\, cm$.First,find the slant height $(l)$ of the cone: $l = \sqrt{r^2 + h^2} = \sqrt{7^2 + 24^2} = \sqrt{49 + 576} = \sqrt{625} = 25\, cm$.The surface area to be painted consists of the curved surface area of the cone and the curved surface area of the hemisphere.Curved Surface Area of Cone = $\pi rl = \frac{22}{7} 	imes 7 	imes 25 = 550\, cm^2$.Curved Surface Area of Hemisphere = $2\pi r^2 = 2 	imes \frac{22}{7} 	imes 7 	imes 7 = 308\, cm^2$.Total Surface Area = $550 + 308 = 858\, cm^2$.Cost of painting = Total Surface Area $	imes$ Rate = $858 	imes 2 = ₹ 1716$.

The base of a cone with radius $7\, cm$ and height $24\, cm$ is hemispherical. Find the cost of painting its surface at the rate of ₹ $2/cm^2$. (in ₹)

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