The batting average of a cricket player for 6 | vedclass

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(D) Let $H$ be the highest score and $L$ be the lowest score.Total runs for $64$ innings $= 64 	imes 62 = 3968$.After excluding the two innings,the n

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$214$

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(D) Let $H$ be the highest score and $L$ be the lowest score.Total runs for $64$ innings $= 64 	imes 62 = 3968$.After excluding the two innings,the number of remaining innings is $64 - 2 = 62$.Total runs for the remaining $62$ innings $= 62 	imes 60 = 3720$.The sum of the highest and lowest scores is $H + L = 3968 - 3720 = 248$.We are given that $H - L = 180$.Adding the two equations: $(H + L) + (H - L) = 248 + 180$.$2H = 428$.$H = 214$.Thus,the highest score is $214$ runs.

The batting average of a cricket player for $64$ innings is $62$ runs. His highest score exceeds his lowest score by $180$ runs. Excluding these two innings,the average of the remaining innings becomes $60$ runs. His highest score was (in $Runs$):

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