The reaction given below is known as:
$ArN_2^+ X^- + Cu_2Cl_2 + HCl \to ArCl + N_2 + Cu_2Cl_2$

  • A
    Chlorination
  • B
    Sandmeyer's reaction
  • C
    Perkin reaction
  • D
    Substitution reaction

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The product formed when aniline is treated with chloroform in the presence of $KOH$ (alcoholic) is

The major product of the reaction is:
$R-CONH_2 \xrightarrow{NaOBr} (A)$
(where $R$ is the chiral group shown in the image)

For the diazonium ions,the order of reactivity towards the diazo-coupling with phenol in the presence of dilute $NaOH$ is:
$(I)$ $Me_2N-C_6H_4-N_2^+$
$(II)$ $O_2N-C_6H_4-N_2^+$
$(III)$ $CH_3O-C_6H_4-N_2^+$
$(IV)$ $CH_3-C_6H_4-N_2^+$

The major product of the following reaction is:
$CH_3-CH(OH)-CH_2-CH_2-NH_2 \xrightarrow[triethylamine]{ethyl\ formate\ (1\ equiv)}$

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