The binaphthol (Bnp) is | vedclass

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Question

(D) The molecule $1,1'-bi-2-naphthol$ $(Bnp)$ exhibits atropisomerism due to restricted rotation about the single bond connecting the two naphthyl rin

Vedclass · Accepted Answer

an optically active compound without having chiral centre

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(D) The molecule $1,1'-bi-2-naphthol$ $(Bnp)$ exhibits atropisomerism due to restricted rotation about the single bond connecting the two naphthyl rings.This restricted rotation arises from the steric hindrance between the hydroxyl groups and the hydrogen atoms at the $8$ and $8'$ positions.As a result,the molecule lacks a plane of symmetry and a center of symmetry,making it chiral.However,it does not possess any traditional $sp^3$ hybridized chiral carbon centers.Therefore,it is an optically active compound without having a chiral center.

The binaphthol $(Bnp)$ is

Similar Questions

$X$ and $Y$ are optically active isomers having the molecular formula $C_5H_9Cl$. When treated with one mole of $H_2$,$X$ gets converted to an optically inactive compound $Z$,but $Y$ gives an optically active compound $P$. The structures of $X$ and $Y$ respectively are:

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