The binding energy of deuteron $_1^2H$ is $1.112 \, MeV$ per nucleon and an $\alpha$-particle $_2^4He$ has a binding energy of $7.047 \, MeV$ per nucleon. Then in the fusion reaction $_1^2H + _1^2H \to _2^4He + Q$,the energy $Q$ released is ........ $MeV$.

  • A
    $1$
  • B
    $11.9$
  • C
    $23.8$
  • D
    $931$

Explore More

Similar Questions

In a nuclear reactor, the main purpose of the moderator is to

Nuclear fission is possible because the binding energy per nucleon ..........

Suppose we think of the fission of a $^{56}_{26} Fe$ nucleus into two equal fragments,$^{28}_{13} Al$. Is the fission energetically possible? Argue by working out the $Q$-value of the process.
Given: $m(^{56}_{26} Fe) = 55.93494 \; u$ and $m(^{28}_{13} Al) = 27.98191 \; u$.

The operation of a nuclear reactor is said to be critical when the value of the neutron multiplication factor $K$ is:

Which nuclear process occurs in a hydrogen bomb? Or,state the principle of a hydrogen bomb.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo