The binding energy of deuteron is 2.2 , MeV a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The nuclear fusion reaction is given by: $_{1}^{2}H + _{1}^{2}H \rightarrow _{2}^{4}He + Q$.The energy released $(Q)$ in a nuclear reaction is equ

Vedclass · Accepted Answer

$23.6$

Vedclass · Answer

(C) The nuclear fusion reaction is given by: $_{1}^{2}H + _{1}^{2}H ightarrow _{2}^{4}He + Q$.The energy released $(Q)$ in a nuclear reaction is equal to the difference between the total binding energy of the products and the total binding energy of the reactants.$Q = B.E.(_{2}^{4}He) - 2 	imes B.E.(_{1}^{2}H)$.Given:$B.E.(_{2}^{4}He) = 28 \, MeV$$B.E.(_{1}^{2}H) = 2.2 \, MeV$Substituting the values:$Q = 28 - 2(2.2) \, MeV$$Q = 28 - 4.4 \, MeV$$Q = 23.6 \, MeV$.Therefore,the energy released is $23.6 \, MeV$.

The binding energy of deuteron is $2.2 \, MeV$ and that of $_2^4He$ is $28 \, MeV$. If two deuterons are fused to form one $_2^4He$,then the energy released is ......... $MeV$.

Similar Questions

$A$ tokamak fusion test reactor works on

The best neutron moderator is:

Which of the following statements is correct?

$A$ nucleus with mass number $A = 240$ and binding energy per nucleon $= 7.6 \,MeV$ breaks into two fragments each of $A = 120$ with binding energy per nucleon $= 8.5 \,MeV$. Calculate the released energy.

In the proton-proton cycle, four hydrogen nuclei combine to release energy of ....... $MeV$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module